
問題の解答

検索用コード(LaTeX)
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% 例題A2.2.15:期待値(さいころの目)(One More)★
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2個のさいころを同時に投げるとき,出る目の差の絶対値の期待値を求めよ.
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% 例題A2.2.15の解答(One More)★
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2個のさいころをA,Bとすると,目の差の絶対値は,右の表のようになり,目の出方は$6\times 6=36(\text{通り})$
したがって,A,Bの出た目の差の絶対値を$X$とすると,$X$のとりうる値とそれぞれの値をとる確率は,下の表のようになる.
\begin{tabular}{|c|c|c|c|c|c|c|}
\hline A$\backslash$B&1&2&3&4&5&6\\
\hline 1&0&1&2&3&4&5\\
\hline 2&1&0&1&2&3&4\\
\hline 3&2&1&0&1&2&3\\
\hline 4&3&2&1&0&1&2\\
\hline 5&4&3&2&1&0&1\\
\hline 6&5&4&3&2&1&0\\
\hline
\end{tabular}
\begin{tabular}{|c||c|c|c|c|c|c|c|}
\hline$X$&0&1&2&3&4&5&計\\
\hline 確率&$\frac{6}{36}$&$\frac{10}{36}$&$\frac{8}{36}$&$\frac{6}{36}$&$\frac{4}{36}$&$\frac{2}{36}$&1\\
\hline
\end{tabular}
よって,求める期待値は,
\[
0\times\frac{6}{36}+1\times\frac{10}{36}+2\times\frac{8}{36}+3\times\frac{6}{36}+4\times\frac{4}{36}+5\times\frac{2}{36}=\frac{35}{18}
\]
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% 問題A2.2.15:期待値(さいころの目)(One More)★
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2個のさいころを同時に投げるとき,出る目の和の期待値を求めよ.
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% 問題A2.2.15の解答(One More)★
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2個のさいころA,Bの出た目の和を$X$とすると,各目の出方に対する$X$の値は,右の表のようになり,目の出方は,$6\times 6=36\text{(通り)}$である.
右の表から,$X$のとりうる値とそれぞれの値をとる確率は,下の表のようになる.
\begin{tabular}{|c|c|c|c|c|c|c|}
\hline A$\backslash$B&1&2&3&4&5&6\\
\hline 1&2&3&4&5&6&7\\
\hline 2&3&4&5&6&7&8\\
\hline 3&4&5&6&7&8&9\\
\hline 4&5&6&7&8&9&10\\
\hline 5&6&7&8&9&10&11\\
\hline 6&7&8&9&10&11&12\\
\hline
\end{tabular}
\begin{tabular}{|c||c|c|c|c|c|c|c|c|c|c|c|c|}
\hline$X$&2&3&4&5&6&7&8&9&10&11&12&計\\
\hline 確率&$\frac{1}{36}$&$\frac{2}{36}$&$\frac{3}{36}$&$\frac{4}{36}$&$\frac{5}{36}$&$\frac{6}{36}$&$\frac{5}{36}$&$\frac{4}{36}$&$\frac{3}{36}$&$\frac{2}{36}$&$\frac{1}{36}$&1\\
\hline
\end{tabular}
よって,求める期待値は,
\begin{align*}
&2\times\frac{1}{36}+3\times\frac{2}{36}+4\times\frac{3}{36}+5\times\frac{4}{36}+6\times\frac{5}{36}+7\times\frac{6}{36}\\
&+8\times\frac{5}{36}+9\times\frac{4}{36}+10\times\frac{3}{36}+11\times\frac{2}{36}+12\times\frac{1}{36}\\
=&7
\end{align*}
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