
問題の解答

検索用コード(LaTeX)
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% 例題I1.3.2:1次不等式(基本)(One More)★
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次の1次不等式を解け.
(1) $3x-2<4x+1$
(2) $2(x+1)\leqq 3(2x-1)$
(3) $\frac{x+1}{6}-4\geqq\frac{x}{3}-\frac{7}{2}$
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% 例題I1.3.2の解答(One More)★
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(1) 移項すると,$3x-4x<1+2$整理すると,$-x<3$
よって,$x>-3$
(2) 展開すると,$2x+2\leqq 6x-3$移項すると,$2x-6x\leqq-3-2$
整理すると,$-4x\leqq-5$
よって,$x\geqq\frac{5}{4}$
(3) 両辺に$6$を掛けると,$x+1-24\geqq 2x-21$移項すると,$x-2x\geqq-21+23$
整理すると,$-x\geqq 2$
よって,$x\leqq-2$
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% 問題I1.3.2:1次不等式(基本)(One More)★
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次の1次不等式を解け.
(1) $5x+1<3x-4$
(2) $4(2x-3)>3(x+2)$
(3) $\frac{2x+3}{4}-\frac{x-1}{6}\geqq\frac{1}{3}$
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% 問題I1.3.2の解答(One More)★
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(1) 移項すると,$5x-3x<-4-1$整理すると,$2x<-5$
よって,$x<-\frac{5}{2}$
(2) 展開すると,$8x-12>3x+6$移項すると,$8x-3x>6+12$
整理すると,$5x>18$
よって,$x>\frac{18}{5}$
(3) 両辺に$12$を掛けると,$3(2x+3)-2(x-1)\geqq 4$展開すると,$6x+9-2x+2\geqq 4$
整理すると,$4x+11\geqq 4$
移項すると,$4x\geqq-7$
よって,$x\geqq-\frac{7}{4}$
あわせて読みたい


【数学I】1章:数と式(基本事項)
検索用コード(LaTeX) 本文・解答側注 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% % 基本事項I1.1.1:単項式と多項式(One More) %%%%%%%%%%%%%%%%%%%%%%%%...
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