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【数学A】例題1.2.7:重複順列(One More)★★

【数学A】例題1.2.7:重複順列(One More)
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【数学A】問題1.2.7:重複順列の解答
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(1) 5人でじゃんけんを1回するとき,5人のグー,チョキ,パーの手の出し方は何通りあるか.

(2) 集合$A=\{a,b,c,d,e\}$の部分集合は全部で何個あるか.

(3) 0,1,2,3の4個の数字の中から,重複を許して4個取って1列に並べるとき,4桁の整数は何個できるか.

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(1) 1人の手の出し方はグー,チョキ,パーの3通りずつある.

よって,5人の手の出し方は,

\[
3\times 3\times 3\times 3\times 3=3^5=243(\text{通り})
\]

(2) 集合$A$の部分集合の個数は,$A$の5つの要素$a,b,c,d,e$のそれぞれが,部分集合に属しているか否かの決め方の数だけある.

よって,集合$A$の部分集合の個数は,

\[
2^5=32\text{(個)}
\]

(3) 千の位に並べる数は,1,2,3の3通り

そのそれぞれについて,百の位と十の位と一の位に並べる数は,0,1,2,3のいずれでもよいから,その個数は,$4^3$通り

よって,求める4桁の整数の個数は,

\[
3\times 4^3=192(\text{個})
\]

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(1) 集合$A=\{x,y,z,w\}$の部分集合は全部で何個あるか.

(2) 0,1,2,3,4の5個の数字の中から,重複を許して3個取って1列に並べるとき,3桁の整数は何個できるか.

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(1) 集合$A$の部分集合の個数は,$A$の4つの要素$x,y,z,w$のそれぞれが,部分集合に属しているか否かの決め方の数だけある.

よって,集合$A$の部分集合の個数は,

\[
2^4=16\text{(個)}
\]

(2) 百の位に並べる数は,1,2,3,4の4通り

そのそれぞれについて,十の位と一の位に並べる数は,0,1,2,3,4のいずれでもよいから,その個数は,$5^2$通り

よって,求める3桁の整数の個数は,

\[
4\times 5^2=100(\text{個})
\]

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