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【数学A】例題3.2.1:円に内接する四角形(One More)★★

【数学A】例題3.2.1:円に内接する四角形(One More)
【数学A】例題3.2.1:円に内接する四角形の例題ページ
問題の解答

【数学A】問題3.2.1:円に内接する四角形の解答
検索用コード(LaTeX)
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右の図において,四角形$\mathrm{ABCD}$は円に内接している.$\angle\mathrm{BEC}=40^{\circ}$,$\angle\mathrm{AFB}=50^{\circ}$のとき,$\angle\mathrm{ABC}$と$\angle\mathrm{BAF}$の大きさを求めよ.

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$\angle\mathrm{ABC}=x$,$\angle\mathrm{BAF}=y$とおく.

四角形$\mathrm{ABCD}$は円に内接するから,

\[
\angle\mathrm{BAD}+\angle\mathrm{BCD}=180^{\circ}
\]

したがって,$\angle\mathrm{ECB}=180^{\circ}-\angle\mathrm{BAF}=180^{\circ}-y$

$\triangle\mathrm{BCE}$の内角の和は$180^{\circ}$であるから,

\[
x+(180^{\circ}-y)+40^{\circ}=180^{\circ}
\]

ゆえに,$y-x=40^{\circ}\cdots(\mathrm{i})$

$\triangle\mathrm{ABF}$の内角の和は$180^{\circ}$であるから,

\[
x+y+50^{\circ}=180^{\circ}
\]

したがって,$x+y=130^{\circ}\cdots(\mathrm{ii})$

(i),(ii)より,$x=45^{\circ}$,$y=85^{\circ}$

よって,$\angle\mathrm{ABC}=45^{\circ}$,$\angle\mathrm{BAF}=85^{\circ}$

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右の図において,四角形$\mathrm{ABCD}$は円に内接している.$\angle\mathrm{AEC}=30^{\circ}$,$\angle\mathrm{EAD}=20^{\circ}$,$\angle\mathrm{ECD}=10^{\circ}$のとき,$\angle\mathrm{ABC}$の大きさを求めよ.

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四角形$\mathrm{ABCD}$は円に内接するから,$\angle\mathrm{BAD}+\angle\mathrm{BCD}=180^{\circ}$

四角形ABCEの内角の和は$360^\circ$であるから,

\[
\angle\mathrm{ABC}+180^{\circ}+20^{\circ}+30^{\circ}+10^{\circ}=360^{\circ}
\]

よって,$\angle\mathrm{ABC}=120^{\circ}$

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