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【数学I】例題1.3.2:1次不等式(基本)(One More)★

【数学I】例題1.3.2:1次不等式(基本)(One More)
【数学I】例題1.3.2:1次不等式(基本)の例題ページ
問題の解答

【数学I】問題1.3.2:1次不等式(基本)の解答
検索用コード(LaTeX)
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次の1次不等式を解け.

(1) $3x-2<4x+1$

(2) $2(x+1)\leqq 3(2x-1)$

(3) $\frac{x+1}{6}-4\geqq\frac{x}{3}-\frac{7}{2}$

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(1) 移項すると,$3x-4x<1+2$整理すると,$-x<3$

よって,$x>-3$

(2) 展開すると,$2x+2\leqq 6x-3$移項すると,$2x-6x\leqq-3-2$

整理すると,$-4x\leqq-5$

よって,$x\geqq\frac{5}{4}$

(3) 両辺に$6$を掛けると,$x+1-24\geqq 2x-21$移項すると,$x-2x\geqq-21+23$

整理すると,$-x\geqq 2$

よって,$x\leqq-2$

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次の1次不等式を解け.

(1) $5x+1<3x-4$

(2) $4(2x-3)>3(x+2)$

(3) $\frac{2x+3}{4}-\frac{x-1}{6}\geqq\frac{1}{3}$

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(1) 移項すると,$5x-3x<-4-1$整理すると,$2x<-5$

よって,$x<-\frac{5}{2}$

(2) 展開すると,$8x-12>3x+6$移項すると,$8x-3x>6+12$

整理すると,$5x>18$

よって,$x>\frac{18}{5}$

(3) 両辺に$12$を掛けると,$3(2x+3)-2(x-1)\geqq 4$展開すると,$6x+9-2x+2\geqq 4$

整理すると,$4x+11\geqq 4$

移項すると,$4x\geqq-7$

よって,$x\geqq-\frac{7}{4}$

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