
問題の解答

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% 例題I3.3.35:2つの放物線の大小関係2(One More)★★★★
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2つの2次関数$f(x)=x^2+2x-2,g(x)=-x^2+2x+a+1$について,次の条件を満たすような定数$a$の値の範囲をそれぞれ求めよ.
(1) $-2\leqq x\leqq 2$を満たすすべての実数$x_1,x_2$に対して,$f(x_1)<g(x_2)$
(2) $-2\leqq x\leqq 2$を満たすある実数$x_1,x_2$に対して,$f(x_1)<g(x_2)$
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% 例題I3.3.35の解答(One More)★★★★
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\[
f(x)=x^2+2x-2=(x+1)^2-3,
\]
\[
g(x)=-x^2+2x+a+1=-(x-1)^2+a+2
\]
(1) $-2\leqq x\leqq 2$を満たすすべての実数$x_1,x_2$に対して$f(x_1)<g(x_2)$が成り立つ条件は,$-2\leqq x\leqq 2$において,「$(f(x)$の最大値)$<(g(x)$の最小値)」が成り立つときである.
$-2\leqq x\leqq 2$において,$f(x)$の最大値は,$f(2)=6$,$g(x)$の最小値は,$g(-2)=a-7$
したがって,$a-7>6$
よって,$a>13$
(2) $-2\leqq x\leqq 2$を満たすある実数$x_1,x_2$に対して$f(x_1)<g(x_2)$が成り立つ条件は,$-2\leqq x\leqq 2$において,「$(f(x)$の最小値)$<(g(x)$の最大値)」が成り立つときである.
$-2\leqq x\leqq 2$において,$f(x)$の最小値は,$f(-1)=-3$,$g(x)$の最大値は,$g(1)=a+2$
したがって,$a+2>-3$
よって,$a>-5$
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% 問題I3.3.35:2つの放物線の大小関係2(One More)★★★★
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2つの2次関数$f(x)=x^2-4x+5,g(x)=-x^2+a-3$について,次の条件を満たすような定数$a$の値の範囲をそれぞれ求めよ.
(1) $-1\leqq x\leqq 3$を満たすすべての実数$x_1,x_2$に対して,$f(x_1)<g(x_2)$
(2) $-1\leqq x\leqq 3$を満たすある実数$x_1,x_2$に対して,$f(x_1)<g(x_2)$
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% 問題I3.3.35の解答(One More)★★★★
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\[
f(x)=x^2-4x+5=(x-2)^2+1
\]
(1) $-1\leqq x\leqq 3$を満たすすべての実数$x_1,x_2$に対して$f(x_1)<g(x_2)$が成り立つ条件は,$-1\leqq x\leqq 3$において,「$(f(x)$の最大値)$<(g(x)$の最小値)」が成り立つときである.
$-1\leqq x\leqq 3$において,$f(x)$の最大値は,$f(-1)=10$,$g(x)$の最小値は,$g(3)=a-12$
したがって,$a-12>10$
よって,$a>22$
(2) $-1\leqq x\leqq 3$を満たすある実数$x_1,x_2$に対して$f(x_1)<g(x_2)$が成り立つ条件は,$-1\leqq x\leqq 3$において,「$(f(x)$の最小値)$<(g(x)$の最大値)」が成り立つときである.
$-1\leqq x\leqq 3$において,$f(x)$の最小値は,$f(2)=1$,$g(x)$の最大値は,$g(0)=a-3$
したがって,$a-3>1$
よって,$a>4$
動的教材(例題3.3.35)
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【数学I】3章:2次関数(基本事項)
検索用コード(LaTeX) 本文・解答側注 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% % 基本事項I3.1.1:関数(One More) %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%...
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