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【数学I】例題3.3.35:2つの放物線の大小関係2(One More)★★★★

【数学I】例題3.3.35:2つの放物線の大小関係2(One More)
【数学I】例題3.3.35:2つの放物線の大小関係2の例題ページ
問題の解答

【数学I】問題3.3.35:2つの放物線の大小関係2の解答
検索用コード(LaTeX)
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2つの2次関数$f(x)=x^2+2x-2,g(x)=-x^2+2x+a+1$について,次の条件を満たすような定数$a$の値の範囲をそれぞれ求めよ.

(1) $-2\leqq x\leqq 2$を満たすすべての実数$x_1,x_2$に対して,$f(x_1)<g(x_2)$

(2) $-2\leqq x\leqq 2$を満たすある実数$x_1,x_2$に対して,$f(x_1)<g(x_2)$

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\[
f(x)=x^2+2x-2=(x+1)^2-3,
\]

\[
g(x)=-x^2+2x+a+1=-(x-1)^2+a+2
\]

(1) $-2\leqq x\leqq 2$を満たすすべての実数$x_1,x_2$に対して$f(x_1)<g(x_2)$が成り立つ条件は,$-2\leqq x\leqq 2$において,「$(f(x)$の最大値)$<(g(x)$の最小値)」が成り立つときである.

$-2\leqq x\leqq 2$において,$f(x)$の最大値は,$f(2)=6$,$g(x)$の最小値は,$g(-2)=a-7$

したがって,$a-7>6$

よって,$a>13$

(2) $-2\leqq x\leqq 2$を満たすある実数$x_1,x_2$に対して$f(x_1)<g(x_2)$が成り立つ条件は,$-2\leqq x\leqq 2$において,「$(f(x)$の最小値)$<(g(x)$の最大値)」が成り立つときである.

$-2\leqq x\leqq 2$において,$f(x)$の最小値は,$f(-1)=-3$,$g(x)$の最大値は,$g(1)=a+2$

したがって,$a+2>-3$

よって,$a>-5$

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2つの2次関数$f(x)=x^2-4x+5,g(x)=-x^2+a-3$について,次の条件を満たすような定数$a$の値の範囲をそれぞれ求めよ.

(1) $-1\leqq x\leqq 3$を満たすすべての実数$x_1,x_2$に対して,$f(x_1)<g(x_2)$

(2) $-1\leqq x\leqq 3$を満たすある実数$x_1,x_2$に対して,$f(x_1)<g(x_2)$

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\[
f(x)=x^2-4x+5=(x-2)^2+1
\]

(1) $-1\leqq x\leqq 3$を満たすすべての実数$x_1,x_2$に対して$f(x_1)<g(x_2)$が成り立つ条件は,$-1\leqq x\leqq 3$において,「$(f(x)$の最大値)$<(g(x)$の最小値)」が成り立つときである.

$-1\leqq x\leqq 3$において,$f(x)$の最大値は,$f(-1)=10$,$g(x)$の最小値は,$g(3)=a-12$

したがって,$a-12>10$

よって,$a>22$

(2) $-1\leqq x\leqq 3$を満たすある実数$x_1,x_2$に対して$f(x_1)<g(x_2)$が成り立つ条件は,$-1\leqq x\leqq 3$において,「$(f(x)$の最小値)$<(g(x)$の最大値)」が成り立つときである.

$-1\leqq x\leqq 3$において,$f(x)$の最小値は,$f(2)=1$,$g(x)$の最大値は,$g(0)=a-3$

したがって,$a-3>1$

よって,$a>4$

動的教材(例題3.3.35)

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