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【数学I】例題2.1.5:3つの集合の共通部分,和集合(One More)★★

【数学I】例題2.1.5:3つの集合の共通部分,和集合(One More)
【数学I】例題2.1.5:3つの集合の共通部分,和集合の例題ページ
問題の解答

【数学I】問題2.1.5:3つの集合の共通部分,和集合の解答
検索用コード(LaTeX)
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% 例題I2.1.5:3つの集合の共通部分,和集合(One More)★★
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$U=\{1,2,3,4,5,6,7,8,9,10,11,12\}$を全体集合とする.$U$の部分集合$A,B,C$を$A=\{n\mid n\text{は12の正の約数}\}$,$B=\{n\mid n\text{は奇数}\}$,$C=\{n\mid n\text{は10の正の約数}\}$とするとき,次の集合を求めよ.

(1) $A\cap B\cap C$

(2) $(A\cup B)\cap C$

(3) $(A\cap C)\cup(B\cap C)$

(4) $\overline{A}\cap\overline{B}\cap\overline{C}$

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% 例題I2.1.5の解答(One More)★★
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$A=\{1,2,3,4,6,12\},B=\{1,3,5,7,9,11\},C=\{1,2,5,10\}$であり,与えられた条件をもとに,$U,A,B,C$をベン図で表すと,下の図のようになる.

(1) $A\cap B\cap C$は,$A$,$B$,$C$の共通部分であるから,

\[
A\cap B\cap C=\{1\}
\]

(2) $A\cup B=\{1,2,3,4,5,6,7,9,11,12\}$より,

\[
(A\cup B)\cap C=\{1,2,5\}
\]

(3) $A\cap C=\{1,2\},B\cap C=\{1,5\}$より,

\[
(A\cap C)\cup(B\cap C)=\{1,2,5\}
\]

(4) ド・モルガンの法則より,

\[
\overline{A}\cap\overline{B}\cap\overline{C}=\overline{A\cup B\cup C}=\{8\}
\]

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% 問題I2.1.5:3つの集合の共通部分,和集合(One More)★★
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$U=\{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15\}$を全体集合とする.$U$の部分集合$A,B,C$を$A=\{n\mid n\text{は10の正の約数}\}$,$B=\{n\mid n\text{は偶数}\}$,$C=\{n\mid n\text{は14の正の約数}\}$とするとき,次の集合を求めよ.

(1) $A\cap B\cap C$

(2) $(A\cup B)\cap C$

(3) $(A\cap C)\cup(B\cap C)$

(4) $\overline{(\overline{A}\cap\overline{C})\cup(\overline{B}\cap\overline{C})}$

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% 問題I2.1.5の解答(One More)★★
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$A=\{1,2,5,10\},B=\{2,4,6,8,10,12,14\},C=\{1,2,7,14\}$であり,与えられた条件をもとに,$U,A,B,C$をベン図で表すと,下の図のようになる.

(1) $A\cap B\cap C$は,$A$,$B$,$C$の共通部分であるから,

\[
A\cap B\cap C=\{2\}
\]

(2) $A\cup B=\{1,2,4,5,6,8,10,12,14\}$より,

\[
(A\cup B)\cap C=\{1,2,14\}
\]

(3) $A\cap C=\{1,2\},B\cap C=\{2,14\}$より,

\[
(A\cap C)\cup(B\cap C)=\{1,2,14\}
\]

(4) ド・モルガンの法則より,

\begin{align*}
\overline{(\overline{A}\cap\overline{C})\cup(\overline{B}\cap\overline{C})}&=\overline{(\overline{A}\cap\overline{C})}\cap\overline{(\overline{B}\cap\overline{C})}\\
&=(\overline{\overline{A}}\cup\overline{\overline{C}})\cap(\overline{\overline{B}}\cup\overline{\overline{C}})\\
&=(A\cup C)\cap(B\cup C)\\
&=(A\cap B)\cup C\\
&=\{1,2,7,10,14\}
\end{align*}

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