
問題の解答

検索用コード(LaTeX)
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% 例題A1.2.15:同じものを含む順列(One More)★
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次の問いに答えよ.
(1) $a,a,b,b,b,b$の6文字を1列に並べる順列は何通りあるか.
(2) 赤色のカード3枚,青色のカード3枚,緑色のカード1枚の合計7枚を1列に並べる順列は何通りあるか.
(3) 赤玉5個と白玉4個の合計9個を1列に並べる順列は何通りあるか.
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% 例題A1.2.15の解答(One More)★
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(1) 2個の$a$と4個の$b$を含む6個の順列であるから,
\[
\frac{6!}{2!4!}=\frac{6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1}{2\cdot 1\cdot 4\cdot 3\cdot 2\cdot 1}=15\text{(通り)}
\]
(2) 3枚の赤色のカードと3枚の青色のカード,1枚の緑色のカードを含む7枚の順列であるから,
\[
\frac{7!}{3!3!1!}=\frac{7\cdot 6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1}{3\cdot 2\cdot 1\cdot 3\cdot 2\cdot 1\cdot 1}=140\text{(通り)}
\]
(3) 5個の赤玉と4個の白玉を含む9個の順列であるから,
\[
\frac{9!}{5!4!}=\frac{9\cdot 8\cdot 7\cdot 6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1}{5\cdot 4\cdot 3\cdot 2\cdot 1\cdot 4\cdot 3\cdot 2\cdot 1}=126\text{(通り)}
\]
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% 例題A1.2.15の別解
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(1) ${}_6\mathrm{C}_2=15$\text{(通り)}
(2) ${}_7\mathrm{C}_3\times{}_4\mathrm{C}_3\times{}_1\mathrm{C}_1=35\times 4\times 1=140$\text{(通り)}
(3) ${}_9\mathrm{C}_5=126$\text{(通り)}
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% 問題A1.2.15:同じものを含む順列(One More)★
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次の問いに答えよ.
(1) $x,x,x,y,y,z$の6文字を1列に並べる順列は何通りあるか.
(2) 青玉6個と緑玉3個の合計9個を1列に並べる順列は何通りあるか.
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% 問題A1.2.15の解答(One More)★
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(1) 3個の$x$,2個の$y$,1個の$z$を含む6個の順列であるから,
\[
\frac{6!}{3!2!1!}=\frac{6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1}{3\cdot 2\cdot 1\cdot 2\cdot 1\cdot 1}=60\text{(通り)}
\]
(2) 6個の青玉と3個の緑玉を含む9個の順列であるから,
\[
\frac{9!}{6!3!}=\frac{9\cdot 8\cdot 7\cdot 6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1}{6\cdot 5\cdot 4\cdot 3\cdot 2\cdot 1\cdot 3\cdot 2\cdot 1}=84\text{(通り)}
\]
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% 問題A1.2.15の別解
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(1) ${}_6\mathrm{C}_3\times{}_3\mathrm{C}_2=60$\text{(通り)}
(2) ${}_9\mathrm{C}_6=84$\text{(通り)}
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検索用コード(LaTeX) 本文・解答側注 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% % 基本事項A1.1.1:集合(One More) %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%...
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